free energy formula
chemistry 2 ?…can anyone help me pls..im stuck!?
it says to write an equilibrium constant expression and calculate the value of the equilibrium constant for each of the following reactions at 298 K
- and then it says as a hint: calculate the values of standard Gibb’s Free Energy changes first, then use the formula to find the corresponding equilibrium constants.
A.) NaHCO3 (s)–> NaOH (s) + CO2 (g)
I have already found out that Keq=Pco2,but i need help finding the values at equilibrium….can anyone help me pls.
B.) 2 HBr (g) + Cl2 (g) –> 2 HCl (g) + Br2 (g)
Again i have found out:
Keq=(((Phcl)^2) x Pbr2) / (((Phbr)^2) x Pcl2)
thank you soo much!!
find the gibbs energy for CO2
Keq=e^(-gibbs energy/RT)
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